Trapezoidal rule 3

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Evaluate
By using Trapezoidal rule

Solution:-
h= 10-0/10 = 1
y= f(x) = 1/ 1+ x^2

X            y
0            1
1            0.5
2            0.2
3            0.1
4            0.05882
5            0.03846
6            0.02702
7            0.02
8            0.01538
9            0.01219
10          0.00990

Using Trapezoidal rule

Integration of Y dx = h/2 [ (Y0 + Yn) + 2(Y1 + Y2+ .......... Y(n-1) ]

=> 1/2[ (1+0.00990) + 2(0.5+ 0.2 + 0.1 + 0.05882+0.03846 + 0.02702 + 0.02+ 0.01538 + 0.01219) ]
=> 0.5 [ 1.00990 + 2× 0.94485]
=> 0.5 [ 1.00990 + 1.88971 ]
=>  1.449805

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