A body is thrown vertically upwards with an initial velocity u reaches the maximum height in 6s. The ratio of the distance traveled by the body in first second to seventh second is Initial velocity u = g×t = 9.8 ×6 = 58.8 m/s distance S 1 travelled in first second is calculated using " S = u ×t - (1/2)×g×t 2 ", using u = 58.8 m/s, and t = 1 s; S 1 = 58.8 ×1 -(1/2) ×9.8 ×1 ×= 53.9 m Since the paticle reaches maximum height in 6 s, at 7th second travel, its initial velocity is zero. hence distance S 7 travelled in 7th second = (1/2) ×9.8 ×1 ×1 = 4.9 m hence the ratio S 1 / S 7 = 53.9 / 4.9 = 11
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